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    [原]java.util.zip.DataFormatException: invalid distance too far back

    testcs_dn发表于 2015-06-17 11:51:59
    love 0

    解压 war/jar文件时出现以下错误:
    java.util.zip.ZipException: invalid distance too far back
    at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.readFromInflater(ZipArchiveInputStream.java:478)
    at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.readDeflated(ZipArchiveInputStream.java:443)
    at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.read(ZipArchiveInputStream.java:384)
    at java.io.InputStream.read(Unknown Source)
    at org.apache.commons.compress.utils.IOUtils.copy(IOUtils.java:75)
    at org.apache.commons.compress.utils.IOUtils.copy(IOUtils.java:56)
    at com.xunge.AESFileEncoder$1.run(AESFileEncoder.java:149)
    at java.lang.Thread.run(Unknown Source)
    Caused by: java.util.zip.DataFormatException: invalid distance too far back
    at java.util.zip.Inflater.inflateBytes(Native Method)
    at java.util.zip.Inflater.inflate(Unknown Source)
    at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.readFromInflater(ZipArchiveInputStream.java:476)
    … 7 more

    相关代码:

    PipedInputStream pin = new PipedInputStream();
                        PipedOutputStream pout = new PipedOutputStream(pin);
                        new Thread(new Runnable() {
                            public void run() {
                                try {
                                    IOUtils.copy(ais, pout);
    
                                    pout.close();
                                } catch (IOException e) {
                                    // TODO Auto-generated catch block
                                    e.printStackTrace();
                                }
                            }
                        }).start();
    
                        ArchiveInputStream inJar = new ArchiveStreamFactory()
                                .createArchiveInputStream(ArchiveStreamFactory.JAR,
                                        pin);

    以上代码是没有问题,如果使用 pin 的代码和 pin 的声明代码中间隔了太多的代码就会产生此异常。具体没有做试验,也可能是有逻辑判断语句的原因。



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