IT博客汇
  • 首页
  • 精华
  • 技术
  • 设计
  • 资讯
  • 扯淡
  • 权利声明
  • 登录 注册

    Mysql 链表查询

    聂文龙发表于 2016-09-08 10:12:00
    love 0
    SELECT u.user_id,u.user_name,c.ct,sub.cts  FROM `zdh_users` u  

    LEFT JOIN   (select admin_id,count(*) as ct FROM `zdh_users` GROUP by admin_id) as c  
    ON u.user_id = c.admin_id 


    LEFT JOIN   (select admin_id,count(*) as cts FROM `zdh_users` where is_subscribe = 1 GROUP by admin_id) as sub 

    ON u.user_id = sub.admin_id 

    WHERE c.ct >0 

    order by c.ct DESC ,sub.cts DESC,u.user_id ASC
    @import url(http://www.cppblog.com/CuteSoft_Client/CuteEditor/Load.ashx?type=style&file=SyntaxHighlighter.css);@import url(/css/cuteeditor.css);

    聂文龙 2016-09-08 18:12 发表评论


沪ICP备19023445号-2号
友情链接