去落格博客阅读完整排版的Swift 中判断字符串是否有 Emoji 表情
很多时候我们需要判断一个字符、或者说是一句话里是不是包含了emoji,使用 Swift 语言开发 app 也不例外,比如可以使用正则表达式——但很遗憾,似乎不同的语言对于正则表达式的支持区别,
\u这个功能不是到哪都好使的,所以最简单粗暴的办法,我们弄一个字符串,它包含了所有可能会用到的 emoji,然后去检索它:
var emojis = "😬😂😃" if let range = emojis.range(of:"xxx") { }
其实吧,说句良心哈,效率还不错……当然了,这样的结果就是你的列表得时常更新——同时你还得忍受 Xcode 卡得一逼的状态。
所以,网上有一个用 OC 实现的扩展,似乎流传很广:
@implementation NSString (Emoji) + (BOOL)stringContainsEmoji:(NSString *)string { __block BOOL returnValue = NO; [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) { const unichar hs = [substring characterAtIndex:0]; if (0xd800 <= hs && hs <= 0xdbff) { if (substring.length > 1) { const unichar ls = [substring characterAtIndex:1]; const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000; if (0x1d000 <= uc && uc <= 0x1f77f) { returnValue = YES; } } } else if (substring.length > 1) { const unichar ls = [substring characterAtIndex:1]; if (ls == 0x20e3) { returnValue = YES; } } else { if (0x2100 <= hs && hs <= 0x27ff) { returnValue = YES; } else if (0x2B05 <= hs && hs <= 0x2b07) { returnValue = YES; } else if (0x2934 <= hs && hs <= 0x2935) { returnValue = YES; } else if (0x3297 <= hs && hs <= 0x3299) { returnValue = YES; } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) { returnValue = YES; } } }]; return returnValue; }
其实它的原理还是去匹配 Emoji 所在区间,所以,如果我们应用上 Swift 语句以及其特性,那么 Swift 版本就是这样:
extension String { var containsEmoji: Bool { for scalar in unicodeScalars { switch scalar.value { case 0x1F600...0x1F64F, // Emoticons 0x1F300...0x1F5FF, // Misc Symbols and Pictographs 0x1F680...0x1F6FF, // Transport and Map 0x2600...0x26FF, // Misc symbols 0x2700...0x27BF, // Dingbats 0xFE00...0xFE0F: // Variation Selectors return true default: continue } } return false } }
😃是不是很简洁?
代码来自:Check if Swift string contains an emoji or dingbat charater