数值的整数次方 链接到标题 # 给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方。 # 考虑边界情况，base = 0, exponent < 0, exponent = 0 场景。 def equal_zero(num): if abs(num - 0.0) < 0.0000001: return True def power(base, exponent): if equal_zero(base): result = False if exponent == 0: result = 1 result = power(base, abs(exponent) >> 1) result *= result if abs(exponent) & 1 == 1: result *= base if exponent < 0: result = 1.0 / result return result power_value(2, 2)